SOLVED: Loop Invariant (5 points) Use the loop invariant to show that the code below correctly computes the product of all elements in an array A of n integers for any n ≥ 2. 1. First, use induction to show that p = a[0] * a[1] * ... * a[i] is indeed a loop invariant. 2. Then, draw conclusions for the termination of the while loop. Algorithm 1: computeProduct (int[] A, int n) 3: p = A[0] 4: i = 1 5: while i < n do 6:
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SOLVED:(Selection Sort) A selection sort searches an array looking for the smallest element. Then, the smallest element is swapped with the first element of the array. The process is repeated for the subarray beginning with the second element of the array. Each pass of the array results in one element being placed in its proper location. This sort performs comparably to the insertion sort-for an array of n elements, n-1 passes must be made, and for each subarray, n-1 comparisons must be made to
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